pw::allocator::Layout Class Reference

#include <layout.h>

Public Member Functions
constexpr	Layout (size_t size)
constexpr	Layout (size_t size, size_t alignment)
constexpr Layout	Extend (size_t size) const
constexpr Layout	Align (size_t alignment) const
constexpr size_t	size () const
constexpr size_t	alignment () const

Static Public Member Functions
template<typename T >
static constexpr std::enable_if_t<!std::is_array_v< T >, Layout >	Of ()
	Creates a Layout for the given type.
template<typename T >
static constexpr std::enable_if_t< internal::is_bounded_array_v< T >, Layout >	Of ()
	Creates a Layout for the given bounded array type, e.g. Foo[kN].
template<typename T >
static constexpr std::enable_if_t< internal::is_unbounded_array_v< T >, Layout >	Of (size_t count)
	Creates a Layout for the given array type, e.g. Foo[].
static constexpr Layout	Unwrap (const Result< Layout > &result)

Detailed Description

Describes the layout of a block of memory.

Layouts are passed to allocators, and consist of a (possibly padded) size and a power-of-two alignment no larger than the size. Layouts can be constructed for a type T using Layout::Of.

Example:

struct MyStruct {
  uint8_t field1[3];
  uint32_t field2[3];
};
constexpr Layout layout_for_struct = Layout::Of<MyStruct>();

Member Function Documentation

Unwrap()

static constexpr Layout pw::allocator::Layout::Unwrap ( const Result< Layout > &  result )

inlinestaticconstexpr

If the result is okay, returns its contained layout; otherwise, returns a default layout.

---

The documentation for this class was generated from the following file:

• pw_allocator/public/pw_allocator/layout.h